Get new customers every week in SQL Server -

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i have data related customers , number of transactions perform every day. see how many "new" customers each week. data looks following:

custnum    created    revenue 1    2014/10/23    30 4    2014/10/23    20 5    2014/10/23    40 2    2014/10/30    13 3    2014/10/30    45 1    2014/10/30    56

in above (sample) data, can see customer custnum 1 has transactions in consecutive weeks, want new customers next week, ones have never done business in past. in other words, want number of totally new customers each week. result should be:

custcount    created 3    2014/10/23 2    2014/10/30

i tried using following query:

select      count(distinct custnum),      dateadd(wk, datediff(wk, 0, created), 0) date orders created > '2013-01-01' group      dateadd(wk, datediff(wk, 0, created), 0) order     dateadd(wk, datediff(wk, 0, created), 0)

but query gives me number of unique customers each week, want number of new customers every week.

any appreciated.

my understanding of question

i took these statements:

  • i see how many "new" customers each week.
  • [customers] have never done business in past
  • i want number of totally new customers each week

do want

 custcount    created  2            week1    -- customer 1 , 2  1            week2    -- customer 3  2            week3    -- customer 4 , 5  -- option  1            week4    -- customer 6 new , 2 not counted   -- or option b  2            week4    -- customer 6 , 2;                         -- since customer 2 did not order in week3

option a

this query select custnum, datepart ( week , created) weeknumber revenues order custnum returns output provided sample data

custnum    weeknumber  1          31       -- counts 1          44       -- not count, since customer ordered once 2          36       -- counts 3          36       -- counts 3          44       -- not count 4          43       -- counts 5          43       -- counts 5          45       -- not count

first step: filter down records

to first record customer (the new customer) can this:

select distinct custnum, min(created) min_created  revenues  group custnum

second step: counting , grouping week

first used sql grouping customer orders week, can find @ old sqlfiddle . decided use

select count(custnum) countcust      , datepart(week, min_created) week_min_created  (         select distinct custnum, min(created) min_created           revenues group custnum     ) sq group datepart(week, min_created)

on returns

countcust  week_min_created 1          31    -- customer 1 2          36    -- customer 2 , 3 2          43    -- customer 4 , 5 -- nothing week 45 since customer 5 counted

some sample data

this sample data used 

create table revenues  (    custnum int ,     created datetime,    revenue int  );  insert revenues (custnum, created, revenue) values   (1, '20140801', 30),   (2, '20140905', 13), (3, '20140905', 45),   (4, '20141023', 20), (5, '20141023', 40),   (3, '20141030', 45), (1, '20141030', 56),   (5, '20141106', 60);

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