ios - how do you return nil if a certain type is passed to a function in Swift? -

ok trying return nil if type passed function. in case im passing in instance of class "blogpost" , type within blogpost. have array called "types" , have assigned variable videos last index of array. if type passed function return nil (so assuming im going need optional here returning possible nil) have far :-

so in need pass in instance of blog post return nil if type passed in. hope makes sense

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update:

the types array defined follows:

let types : [string] = ["technology", "fashion", "animals"] 

this array referring in function. if last entry of array entered function need return nil

sure blogpost have empty string type

great im getting there ive done change blogpost.type choose 1 @ random. if specfic type chosen array how still getting error. have updated to

so need access 2 type in array , if access return nil. thoughts on that? drag on thanks

you passing blog blogpost.type parameter. not correct. should have either passed string parameter, or pass blogpost itself:

func randomviews(blog: blogpost) {     let videos = types[2]      if blog.type == videos {         // whatever want     }      // carry on } 

unrelated question @ hand, notice use let instead of var when defining videos. use let if value not (and cannot) change.

also note use lowercase letter v in videos, because cocoa naming conventions dictate variables start lowercase letters, whereas types, classes, structs, , enums start uppercase letters.