Trying to access a bash array via function results in ${1[@]}: bad substitution -
there's not code below results in bad substitution.
#!/bin/bash  numbers=(0 1 2 3 4 5 6 7 8 9) charslc=(a b c d e f g h j) charsuc=(a b c d e f g h j)  show () {         # value of var held in $1         in "${1[@]}";          echo $i         done }  # # processing happens here resulting in # var=numbers or # var=charslc or # var=charsuc #  var=numbers # simulating process mentioned above show $var question: how can fixed while ideally sticking type of approach?
define function as:
show() {    arr=$1[@]    in "${!arr}";       echo "$i"    done } and call as:
numbers=(0 1 2 3 4 5 6 7 8 9) var=numbers show "$var" 
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