string - Reading in numbers and names using getline in C++? -

so i've been working on problem hours , help. have program due tomorrow. basically, have input file has first , last name , 4 float numbers following. looks this:

john w. smith 78.8 56.5 34.5 23.3 jane  doe 34.5 23.4 35.7 87.0 no more 

i need read first , last names array of pointers. far trying read in each line variable "name" , i'm outputting text file see if have been reading in data correctly. unfortunately, stops after reads in floats, doesn't read in next names.

char *newptr;                char *namelist[50] = {0};    char name[15];   int = 0;  infile.getline(name, 15);  while (strcmp (name, "no") != 0) {     newptr = new char[15];     strcpy(newptr, name);     namelist[i] = newptr;     infile.getline(name, 15);     outfile << name << endl;     i++; } 

so far, output has been:

john w.

smith

78.8 56.5 34.5 23.3

edit: loop infinite, output, know haven't processed second names yet, stop @ first numbers.

if help, great! limited functions can use, should using getline function here, cannot use fancy.

in slides, teacher has code here reading in names:

char *newptr; char *namelist[6] = {0}; char name[20]; int = 0; infile.getline(name, 20); while(strcmp(name, sentinel) != 0) { newptr = new char[20]; strcpy(newptr,name); namelist[a++] = newptr; infile.getline(name,20); } 

we have not been taught strings yet , cannot use have not talked in class. thank far has commented.

you're there... main thing forgot attempt read numbers. code below reads them w, x, y , z ignores them... should whatever need them, e.g. create second array surnames , either third 2-dimensional array floats or 1-dimensional array 4 times long....

char *namelist[50] = {0};    char name[15];   int = 0;   while (infile.getline(name, sizeof name) && strcmp(name, "no") != 0) {     char* newptr = new char[sizeof name];     strcpy(newptr, name);     namelist[i] = newptr;     double w, x, y, z;     if (infile.getline(name, sizeof name) && infile >> w >> x >> y >> z)         outfile << name << endl;     else     {         std::cerr << "missing rest of data " << namelist[i] << " found\n";         exit(exit_failure)     }     i++; }