python - Simplest way to get the first n elements of an iterator -

how can first n elements of iterator (generator) in simplest way? there simpler than, e. g.

def firstn(iterator, n):   in range(n):     yield iterator.next()  print list(firstn(it, 3))

i can't think of nicer way, maybe there is? maybe functional form?

from itertools import islice print list(islice(it, 3))

this'll yield next 3 elements it, stop.

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