php - Variable as Array Key - Yii Dropdown Selected -
i using yii , have dropdown using following example:
$form->dropdownlist($model,'sex',array('1'=>'men','2'=>'women'), array('options' => array('2'=>array('selected'=>true))));
here able choose option selected. if set 2 shown in example above selected option women expected. not able statically set selected option need use variable. have $selectedid
equal 2, when doing example:
array('options' => array("$selectedid"=>array('selected'=>true))));
or doing this:
array('options' => array($selectedid=>array('selected'=>true))));
i getting no errors, dropdown not have expected selected option. possible use variable when defining array key?
update
true string:
chtml::dropdownlist('package','',chtml::listdata(services::model()->findall(array('condition'=>'is_internet = 1','params'=>array())), 'id', 'name'),array('id'=>'package'))
you can set setting second parameter:
chtml::dropdownlist('package',$selectedid,chtml::listdata(services::model()->findall(array('condition'=>'is_internet = 1','params'=>array())), 'id', 'name'),array('id'=>'package'))
Comments
Post a Comment