jquery - JavaScript array manipulation to delete odd array elements -

i need help; have array this:

myarray = ["nonsense","goodpart","nonsense2","goodpar2t","nonsense3","goodpart3",] 

i need delete "nonsense" part array.

nonsense have index.

i'd suggest, on basis 'nonsense' words (as stated in question) 'even' elements:

var myarray = ["nonsense", "goodpart", "nonsense2", "goodpar2t", "nonsense3", "goodpart3"],    filtered = myarray.filter(function(el, index) {      // numbers have feature number % 2 === 0;      // javascript is, however, zero-based, want elements modulo of 1:      return index % 2 === 1;    });    console.log(filtered); // ["goodpart", "goodpar2t", "goodpart3"]

if, however, wanted filter array-elements themselves, remove words contain word 'nonsense':

var myarray = ["nonsense", "goodpart", "nonsense2", "goodpar2t", "nonsense3", "goodpart3"],    filtered = myarray.filter(function(el) {      // indexof() equal -1 means passed-in string not found:      return el.indexof('nonsense') === -1;    });    console.log(filtered); // ["goodpart", "goodpar2t", "goodpart3"]

or find, , keep, words begin 'good':

var myarray = ["nonsense", "goodpart", "nonsense2", "goodpar2t", "nonsense3", "goodpart3"],    filtered = myarray.filter(function(el) {      // here test word ('el') against regular expression,      // ^good meaning string of 'good' appears @ beginning of      // string:      return (/^good/).test(el);    });    console.log(filtered); // ["goodpart", "goodpar2t", "goodpart3"]

references:

• array.prototype.filter().
• array.prototype.indexof().
• javascript regular expressions.
• regexp.prototype.test().
• string.prototype.indexof().