php - Show multiple values from a row when dropdown box is used from mysql database -

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i'm trying show specific item in row when item in dropdown list selected. clarify, lets have item1 chosen in dropdown menu, , when item1 chosen, want price item1 shown in field on page.

ps. i'm trying make inventory , ordering form connected mysql database.

thanks in advance.

here php code.

    <?php      function dropdown( $alcohol, array $options, $selected=null )     {         /*** begin select ***/         $dropdown = '<select name="'.$alcohol.'" id="'.$alcohol.'">'."\n";          $selected = $selected;         /*** loop on options ***/         foreach( $options $key=>$option )         {             /*** assign selected value ***/             $select = $selected==$key ? ' selected' : null;              /*** add each option dropdown ***/             $dropdown .= '<option                                         `value="'.$key.'"'.$select.'>'.$option.'</option>'."\n";         }      /*** close select ***/     $dropdown .= '</select>'."\n";      /*** , return completed dropdown ***/     return $dropdown; } ?>  <form>  <?php mysql_connect('localhost', 'root', ''); mysql_select_db(''); $sql = "select alcohol alcohol "; $result = mysql_query($sql); echo "<select name='alcohol'>"; while ($row = mysql_fetch_array($result)) {     echo "<option value='" . $row['alcohol'] . "'>" . $row['alcohol'] . "</option>"; } echo "</select>"; ?>  </form>

//new stuff below this//

<form  id="data" class="form_alcohol" role="form" method="post" action="connect.php">             <input type = "submit" name = "submit" value = "submit">             <select size="1" name="alcohol">                 <option value="">--- select alcohol ---</option>                 <?php                     mysql_connect('localhost', 'root', '');                     mysql_select_db('');                     $sql = "select alcohol alcohol";                     $result1 = mysql_query($sql);                      while ($row = mysql_fetch_array($result1)) {                     echo "<option value='" . $row['alcohol'] . "'>" . $row['alcohol'] . "</option>";                     }                     $dropdown1 = empty($_post['alcohol'])? die ("error: select dropdown") : mysql_escape_string($_post['alcohol']); echo "</select>";                  ?>  <?php  if(isset($_post['submit'])) { mysql_connect('localhost', 'root', ''); mysql_select_db(''); $sql = "select * alcohol '$dropdown1' = alcohol"; $result = mysql_query($sql) or die(mysql_error()); ?> <table> <td> alcohol </td> <td> price </td> <td> amount in stock </td>  <?php   while ($row = mysql_fetch_array($result)) {  echo "<tr><td>".$row['alcohol']."</td><td>".$row['price']."</td><td>".$row['quantity_in_stock']."</td>";  } } ?>  </table>

first of all, use mysqli. mysql_* deprecated , removed in future version.

now have out of way, add "marker" character in original dropdown select values in order value. pick unicode character wouldn't in database, , echo in value looks this:

<option value="$name@$price">$name</option>

then in code above, split value @ @ character , pick out after in order secondary value. should save database operation in long run.

good luck!


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