XSLT: Count only when value greater than nul -

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all,

this question related xslt 1.0

is there way count nodes specific value greater null? use sum function total of this:

<servicelevels>     <servicelevel>         <key>0..20</key>         <value>100.00</value>     </servicelevel>     <servicelevel>         <key>20..30</key>         <value>0.00</value>     </servicelevel>     <servicelevel>         <key>30..40</key>         <value>0.00</value>     </servicelevel>     <servicelevel>         <key>40..50</key>         <value>0.00</value>     </servicelevel>     <servicelevel>         <key>50..60</key>         <value>0.00</value>     </servicelevel>     <servicelevel>         <key>60..70</key>         <value>0.00</value>     </servicelevel>     <servicelevel>         <key>70+</key>         <value>98.33</value>     </servicelevel> </servicelevels>

to find sum of value keys, use:

<xsl:value-of select="sum(servicelevels/servicelevel/value | servicelevels/servicelevel/value)"/>

what produces sum of 198.33 calculate the average of 7 nodes use xsl:value-of select="count(....)" calculates 28.333 want find average nodes contain actual values in example 2 nodes creates average of 99.165.

is there (relative simple) way of achieving this?

the xml contains 7 key values

select value nodes content (as number) greater zero:

<xsl:variable name="values" select="servicelevels/servicelevel/value[number(.) &gt; 0]"/>

average:

<xsl:value-of select="sum($values) div count($values)"/>

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