Storing a function inside a bash array element -

how can define function element of array?

i know can this:

function array[5](){ echo "you inside function"; }

and valid function, in sense that, instruction array[5], correctly execute function.

unlucky, function not listed in keys of array, so, echo ${!array[*]} not return 5 key.

for instance, following code:

array[0]="first" function array[5](){ echo "you inside function"; } array[7]="seventh" echo ${!array[*]}

only returns 0 7.

so, how can add function array element, can loop on it?

you can't put function in array. can put function name in field. look:

a_pretty_function() {     echo "you're inside function"; } array[5]=a_pretty_function  # execute it: "${array[5]}"

when you're doing

array[5]() { echo "you inside function"; }

you're defining function called array[5] can check declare -pf array[5].

with mechanism can horribly ugly:

array[5]() { echo "you inside function"; } i=5 "array[$i]"

and execute function array[5]. wouldn't recommend such practice in case.

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