shell - Bash: Directory does not exist -

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what little code snippet do? understand test command. question is: >&2 mean?

if test ! -d "$1" ; echo "directory not exist" >&2 ; exit 6 fi

thanks in advance!

it redirects stdout stderr.

when do:

echo "directory not exist"

the message goes standard output(1) . >&2 redirects standard error (2). useful when want capture stdout , stderr separately.

for example, if in script my_scr.sh running as:

bash my_scr.sh > out_file 2> err_file

will ensure errors captured in err_file , other output goes out_file.

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