concurrency - c++ future call local variable -
when using c++ future call function, if define 2 future objects a,b , call same function foo = async(launch::async,foo); b = async(launch::async,foo); is same running function twice? foo() foo() i.e. a , b each running private copy of foo ? they use same function example shows. void foo() { static int counter=0; cout<<counter++<<endl; return; } int main() { std::future<void> resulta(async(launch::async,foo)); resulta.get(); std::future<void> resultb(async(launch::async,foo)); resultb.get(); return 0; } output: 0 1 this shows same static counter variable used bcz output not 0,0 0, 1 (incremented goes foo) hope helps,
